2x^2+6x-3=2x(x+(19/2))

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Solution for 2x^2+6x-3=2x(x+(19/2)) equation: 



2x^2+6x-3=2x(x+(19/2))

We move all terms to the left:

2x^2+6x-3-(2x(x+(19/2)))=0

We add all the numbers together, and all the variables

2x^2+6x-(2x(x+(+19/2)))-3=0

We multiply all the terms by the denominator


2x^2*2)))+6x*2)))-(2x(x+(+19-3*2)))=0

We add all the numbers together, and all the variables

2x^2*2)))+6x*2)))-(2x(x+13))=0

Wy multiply elements

8x^4=0

We do not support expression: x^4

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